3.136 \(\int \frac {(d+e x^2)^{3/2} (a+b \text {csch}^{-1}(c x))}{x^6} \, dx\)

Optimal. Leaf size=492 \[ -\frac {\left (d+e x^2\right )^{5/2} \left (a+b \text {csch}^{-1}(c x)\right )}{5 d x^5}-\frac {4 b c \sqrt {-c^2 x^2-1} \left (c^2 d-2 e\right ) \sqrt {d+e x^2}}{75 x^2 \sqrt {-c^2 x^2}}+\frac {b c \sqrt {-c^2 x^2-1} \left (d+e x^2\right )^{3/2}}{25 x^4 \sqrt {-c^2 x^2}}+\frac {b c \sqrt {-c^2 x^2-1} \left (8 c^4 d^2-23 c^2 d e+23 e^2\right ) \sqrt {d+e x^2}}{75 d \sqrt {-c^2 x^2}}+\frac {b e x \left (4 c^4 d^2-11 c^2 d e+15 e^2\right ) \sqrt {d+e x^2} F\left (\tan ^{-1}(c x)|1-\frac {e}{c^2 d}\right )}{75 d^2 \sqrt {-c^2 x^2} \sqrt {-c^2 x^2-1} \sqrt {\frac {d+e x^2}{d \left (c^2 x^2+1\right )}}}-\frac {b c^2 x \left (8 c^4 d^2-23 c^2 d e+23 e^2\right ) \sqrt {d+e x^2} E\left (\tan ^{-1}(c x)|1-\frac {e}{c^2 d}\right )}{75 d \sqrt {-c^2 x^2} \sqrt {-c^2 x^2-1} \sqrt {\frac {d+e x^2}{d \left (c^2 x^2+1\right )}}}+\frac {b c^3 x^2 \left (8 c^4 d^2-23 c^2 d e+23 e^2\right ) \sqrt {d+e x^2}}{75 d \sqrt {-c^2 x^2} \sqrt {-c^2 x^2-1}} \]

[Out]

-1/5*(e*x^2+d)^(5/2)*(a+b*arccsch(c*x))/d/x^5+1/25*b*c*(e*x^2+d)^(3/2)*(-c^2*x^2-1)^(1/2)/x^4/(-c^2*x^2)^(1/2)
+1/75*b*c^3*(8*c^4*d^2-23*c^2*d*e+23*e^2)*x^2*(e*x^2+d)^(1/2)/d/(-c^2*x^2)^(1/2)/(-c^2*x^2-1)^(1/2)+1/75*b*c*(
8*c^4*d^2-23*c^2*d*e+23*e^2)*(-c^2*x^2-1)^(1/2)*(e*x^2+d)^(1/2)/d/(-c^2*x^2)^(1/2)-4/75*b*c*(c^2*d-2*e)*(-c^2*
x^2-1)^(1/2)*(e*x^2+d)^(1/2)/x^2/(-c^2*x^2)^(1/2)-1/75*b*c^2*(8*c^4*d^2-23*c^2*d*e+23*e^2)*x*(1/(c^2*x^2+1))^(
1/2)*(c^2*x^2+1)^(1/2)*EllipticE(c*x/(c^2*x^2+1)^(1/2),(1-e/c^2/d)^(1/2))*(e*x^2+d)^(1/2)/d/(-c^2*x^2)^(1/2)/(
-c^2*x^2-1)^(1/2)/((e*x^2+d)/d/(c^2*x^2+1))^(1/2)+1/75*b*e*(4*c^4*d^2-11*c^2*d*e+15*e^2)*x*(1/(c^2*x^2+1))^(1/
2)*(c^2*x^2+1)^(1/2)*EllipticF(c*x/(c^2*x^2+1)^(1/2),(1-e/c^2/d)^(1/2))*(e*x^2+d)^(1/2)/d^2/(-c^2*x^2)^(1/2)/(
-c^2*x^2-1)^(1/2)/((e*x^2+d)/d/(c^2*x^2+1))^(1/2)

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Rubi [A]  time = 0.58, antiderivative size = 492, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 10, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.435, Rules used = {264, 6302, 12, 474, 580, 583, 531, 418, 492, 411} \[ -\frac {\left (d+e x^2\right )^{5/2} \left (a+b \text {csch}^{-1}(c x)\right )}{5 d x^5}+\frac {b c^3 x^2 \left (8 c^4 d^2-23 c^2 d e+23 e^2\right ) \sqrt {d+e x^2}}{75 d \sqrt {-c^2 x^2} \sqrt {-c^2 x^2-1}}+\frac {b c \sqrt {-c^2 x^2-1} \left (8 c^4 d^2-23 c^2 d e+23 e^2\right ) \sqrt {d+e x^2}}{75 d \sqrt {-c^2 x^2}}+\frac {b e x \left (4 c^4 d^2-11 c^2 d e+15 e^2\right ) \sqrt {d+e x^2} F\left (\tan ^{-1}(c x)|1-\frac {e}{c^2 d}\right )}{75 d^2 \sqrt {-c^2 x^2} \sqrt {-c^2 x^2-1} \sqrt {\frac {d+e x^2}{d \left (c^2 x^2+1\right )}}}-\frac {b c^2 x \left (8 c^4 d^2-23 c^2 d e+23 e^2\right ) \sqrt {d+e x^2} E\left (\tan ^{-1}(c x)|1-\frac {e}{c^2 d}\right )}{75 d \sqrt {-c^2 x^2} \sqrt {-c^2 x^2-1} \sqrt {\frac {d+e x^2}{d \left (c^2 x^2+1\right )}}}+\frac {b c \sqrt {-c^2 x^2-1} \left (d+e x^2\right )^{3/2}}{25 x^4 \sqrt {-c^2 x^2}}-\frac {4 b c \sqrt {-c^2 x^2-1} \left (c^2 d-2 e\right ) \sqrt {d+e x^2}}{75 x^2 \sqrt {-c^2 x^2}} \]

Antiderivative was successfully verified.

[In]

Int[((d + e*x^2)^(3/2)*(a + b*ArcCsch[c*x]))/x^6,x]

[Out]

(b*c^3*(8*c^4*d^2 - 23*c^2*d*e + 23*e^2)*x^2*Sqrt[d + e*x^2])/(75*d*Sqrt[-(c^2*x^2)]*Sqrt[-1 - c^2*x^2]) + (b*
c*(8*c^4*d^2 - 23*c^2*d*e + 23*e^2)*Sqrt[-1 - c^2*x^2]*Sqrt[d + e*x^2])/(75*d*Sqrt[-(c^2*x^2)]) - (4*b*c*(c^2*
d - 2*e)*Sqrt[-1 - c^2*x^2]*Sqrt[d + e*x^2])/(75*x^2*Sqrt[-(c^2*x^2)]) + (b*c*Sqrt[-1 - c^2*x^2]*(d + e*x^2)^(
3/2))/(25*x^4*Sqrt[-(c^2*x^2)]) - ((d + e*x^2)^(5/2)*(a + b*ArcCsch[c*x]))/(5*d*x^5) - (b*c^2*(8*c^4*d^2 - 23*
c^2*d*e + 23*e^2)*x*Sqrt[d + e*x^2]*EllipticE[ArcTan[c*x], 1 - e/(c^2*d)])/(75*d*Sqrt[-(c^2*x^2)]*Sqrt[-1 - c^
2*x^2]*Sqrt[(d + e*x^2)/(d*(1 + c^2*x^2))]) + (b*e*(4*c^4*d^2 - 11*c^2*d*e + 15*e^2)*x*Sqrt[d + e*x^2]*Ellipti
cF[ArcTan[c*x], 1 - e/(c^2*d)])/(75*d^2*Sqrt[-(c^2*x^2)]*Sqrt[-1 - c^2*x^2]*Sqrt[(d + e*x^2)/(d*(1 + c^2*x^2))
])

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 264

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[((c*x)^(m + 1)*(a + b*x^n)^(p + 1))/(a
*c*(m + 1)), x] /; FreeQ[{a, b, c, m, n, p}, x] && EqQ[(m + 1)/n + p + 1, 0] && NeQ[m, -1]

Rule 411

Int[Sqrt[(a_) + (b_.)*(x_)^2]/((c_) + (d_.)*(x_)^2)^(3/2), x_Symbol] :> Simp[(Sqrt[a + b*x^2]*EllipticE[ArcTan
[Rt[d/c, 2]*x], 1 - (b*c)/(a*d)])/(c*Rt[d/c, 2]*Sqrt[c + d*x^2]*Sqrt[(c*(a + b*x^2))/(a*(c + d*x^2))]), x] /;
FreeQ[{a, b, c, d}, x] && PosQ[b/a] && PosQ[d/c]

Rule 418

Int[1/(Sqrt[(a_) + (b_.)*(x_)^2]*Sqrt[(c_) + (d_.)*(x_)^2]), x_Symbol] :> Simp[(Sqrt[a + b*x^2]*EllipticF[ArcT
an[Rt[d/c, 2]*x], 1 - (b*c)/(a*d)])/(a*Rt[d/c, 2]*Sqrt[c + d*x^2]*Sqrt[(c*(a + b*x^2))/(a*(c + d*x^2))]), x] /
; FreeQ[{a, b, c, d}, x] && PosQ[d/c] && PosQ[b/a] &&  !SimplerSqrtQ[b/a, d/c]

Rule 474

Int[((e_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_))^(q_), x_Symbol] :> Simp[(c*(e*x)^
(m + 1)*(a + b*x^n)^(p + 1)*(c + d*x^n)^(q - 1))/(a*e*(m + 1)), x] - Dist[1/(a*e^n*(m + 1)), Int[(e*x)^(m + n)
*(a + b*x^n)^p*(c + d*x^n)^(q - 2)*Simp[c*(c*b - a*d)*(m + 1) + c*n*(b*c*(p + 1) + a*d*(q - 1)) + d*((c*b - a*
d)*(m + 1) + c*b*n*(p + q))*x^n, x], x], x] /; FreeQ[{a, b, c, d, e, p}, x] && NeQ[b*c - a*d, 0] && IGtQ[n, 0]
&& GtQ[q, 1] && LtQ[m, -1] && IntBinomialQ[a, b, c, d, e, m, n, p, q, x]

Rule 492

Int[(x_)^2/(Sqrt[(a_) + (b_.)*(x_)^2]*Sqrt[(c_) + (d_.)*(x_)^2]), x_Symbol] :> Simp[(x*Sqrt[a + b*x^2])/(b*Sqr
t[c + d*x^2]), x] - Dist[c/b, Int[Sqrt[a + b*x^2]/(c + d*x^2)^(3/2), x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[b
*c - a*d, 0] && PosQ[b/a] && PosQ[d/c] &&  !SimplerSqrtQ[b/a, d/c]

Rule 531

Int[((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n_))^(q_.)*((e_) + (f_.)*(x_)^(n_)), x_Symbol] :> Dist[
e, Int[(a + b*x^n)^p*(c + d*x^n)^q, x], x] + Dist[f, Int[x^n*(a + b*x^n)^p*(c + d*x^n)^q, x], x] /; FreeQ[{a,
b, c, d, e, f, n, p, q}, x]

Rule 580

Int[((g_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n_))^(q_.)*((e_) + (f_.)*(x_)^(n_)),
x_Symbol] :> Simp[(e*(g*x)^(m + 1)*(a + b*x^n)^(p + 1)*(c + d*x^n)^q)/(a*g*(m + 1)), x] - Dist[1/(a*g^n*(m + 1
)), Int[(g*x)^(m + n)*(a + b*x^n)^p*(c + d*x^n)^(q - 1)*Simp[c*(b*e - a*f)*(m + 1) + e*n*(b*c*(p + 1) + a*d*q)
+ d*((b*e - a*f)*(m + 1) + b*e*n*(p + q + 1))*x^n, x], x], x] /; FreeQ[{a, b, c, d, e, f, g, p}, x] && IGtQ[n
, 0] && GtQ[q, 0] && LtQ[m, -1] &&  !(EqQ[q, 1] && SimplerQ[e + f*x^n, c + d*x^n])

Rule 583

Int[((g_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n_))^(q_.)*((e_) + (f_.)*(x_)^(n_)),
x_Symbol] :> Simp[(e*(g*x)^(m + 1)*(a + b*x^n)^(p + 1)*(c + d*x^n)^(q + 1))/(a*c*g*(m + 1)), x] + Dist[1/(a*c*
g^n*(m + 1)), Int[(g*x)^(m + n)*(a + b*x^n)^p*(c + d*x^n)^q*Simp[a*f*c*(m + 1) - e*(b*c + a*d)*(m + n + 1) - e
*n*(b*c*p + a*d*q) - b*e*d*(m + n*(p + q + 2) + 1)*x^n, x], x], x] /; FreeQ[{a, b, c, d, e, f, g, p, q}, x] &&
IGtQ[n, 0] && LtQ[m, -1]

Rule 6302

Int[((a_.) + ArcCsch[(c_.)*(x_)]*(b_.))*((f_.)*(x_))^(m_.)*((d_.) + (e_.)*(x_)^2)^(p_.), x_Symbol] :> With[{u
= IntHide[(f*x)^m*(d + e*x^2)^p, x]}, Dist[a + b*ArcCsch[c*x], u, x] - Dist[(b*c*x)/Sqrt[-(c^2*x^2)], Int[Simp
lifyIntegrand[u/(x*Sqrt[-1 - c^2*x^2]), x], x], x]] /; FreeQ[{a, b, c, d, e, f, m, p}, x] && ((IGtQ[p, 0] &&
!(ILtQ[(m - 1)/2, 0] && GtQ[m + 2*p + 3, 0])) || (IGtQ[(m + 1)/2, 0] &&  !(ILtQ[p, 0] && GtQ[m + 2*p + 3, 0]))
|| (ILtQ[(m + 2*p + 1)/2, 0] &&  !ILtQ[(m - 1)/2, 0]))

Rubi steps

\begin {align*} \int \frac {\left (d+e x^2\right )^{3/2} \left (a+b \text {csch}^{-1}(c x)\right )}{x^6} \, dx &=-\frac {\left (d+e x^2\right )^{5/2} \left (a+b \text {csch}^{-1}(c x)\right )}{5 d x^5}-\frac {(b c x) \int -\frac {\left (d+e x^2\right )^{5/2}}{5 d x^6 \sqrt {-1-c^2 x^2}} \, dx}{\sqrt {-c^2 x^2}}\\ &=-\frac {\left (d+e x^2\right )^{5/2} \left (a+b \text {csch}^{-1}(c x)\right )}{5 d x^5}+\frac {(b c x) \int \frac {\left (d+e x^2\right )^{5/2}}{x^6 \sqrt {-1-c^2 x^2}} \, dx}{5 d \sqrt {-c^2 x^2}}\\ &=\frac {b c \sqrt {-1-c^2 x^2} \left (d+e x^2\right )^{3/2}}{25 x^4 \sqrt {-c^2 x^2}}-\frac {\left (d+e x^2\right )^{5/2} \left (a+b \text {csch}^{-1}(c x)\right )}{5 d x^5}-\frac {(b c x) \int \frac {\sqrt {d+e x^2} \left (4 d \left (c^2 d-2 e\right )+\left (c^2 d-5 e\right ) e x^2\right )}{x^4 \sqrt {-1-c^2 x^2}} \, dx}{25 d \sqrt {-c^2 x^2}}\\ &=-\frac {4 b c \left (c^2 d-2 e\right ) \sqrt {-1-c^2 x^2} \sqrt {d+e x^2}}{75 x^2 \sqrt {-c^2 x^2}}+\frac {b c \sqrt {-1-c^2 x^2} \left (d+e x^2\right )^{3/2}}{25 x^4 \sqrt {-c^2 x^2}}-\frac {\left (d+e x^2\right )^{5/2} \left (a+b \text {csch}^{-1}(c x)\right )}{5 d x^5}+\frac {(b c x) \int \frac {d \left (8 c^4 d^2-23 c^2 d e+23 e^2\right )+e \left (4 c^4 d^2-11 c^2 d e+15 e^2\right ) x^2}{x^2 \sqrt {-1-c^2 x^2} \sqrt {d+e x^2}} \, dx}{75 d \sqrt {-c^2 x^2}}\\ &=\frac {b c \left (8 c^4 d^2-23 c^2 d e+23 e^2\right ) \sqrt {-1-c^2 x^2} \sqrt {d+e x^2}}{75 d \sqrt {-c^2 x^2}}-\frac {4 b c \left (c^2 d-2 e\right ) \sqrt {-1-c^2 x^2} \sqrt {d+e x^2}}{75 x^2 \sqrt {-c^2 x^2}}+\frac {b c \sqrt {-1-c^2 x^2} \left (d+e x^2\right )^{3/2}}{25 x^4 \sqrt {-c^2 x^2}}-\frac {\left (d+e x^2\right )^{5/2} \left (a+b \text {csch}^{-1}(c x)\right )}{5 d x^5}+\frac {(b c x) \int \frac {d e \left (4 c^4 d^2-11 c^2 d e+15 e^2\right )+c^2 d e \left (8 c^4 d^2-23 c^2 d e+23 e^2\right ) x^2}{\sqrt {-1-c^2 x^2} \sqrt {d+e x^2}} \, dx}{75 d^2 \sqrt {-c^2 x^2}}\\ &=\frac {b c \left (8 c^4 d^2-23 c^2 d e+23 e^2\right ) \sqrt {-1-c^2 x^2} \sqrt {d+e x^2}}{75 d \sqrt {-c^2 x^2}}-\frac {4 b c \left (c^2 d-2 e\right ) \sqrt {-1-c^2 x^2} \sqrt {d+e x^2}}{75 x^2 \sqrt {-c^2 x^2}}+\frac {b c \sqrt {-1-c^2 x^2} \left (d+e x^2\right )^{3/2}}{25 x^4 \sqrt {-c^2 x^2}}-\frac {\left (d+e x^2\right )^{5/2} \left (a+b \text {csch}^{-1}(c x)\right )}{5 d x^5}+\frac {\left (b c e \left (4 c^4 d^2-11 c^2 d e+15 e^2\right ) x\right ) \int \frac {1}{\sqrt {-1-c^2 x^2} \sqrt {d+e x^2}} \, dx}{75 d \sqrt {-c^2 x^2}}+\frac {\left (b c^3 e \left (8 c^4 d^2-23 c^2 d e+23 e^2\right ) x\right ) \int \frac {x^2}{\sqrt {-1-c^2 x^2} \sqrt {d+e x^2}} \, dx}{75 d \sqrt {-c^2 x^2}}\\ &=\frac {b c^3 \left (8 c^4 d^2-23 c^2 d e+23 e^2\right ) x^2 \sqrt {d+e x^2}}{75 d \sqrt {-c^2 x^2} \sqrt {-1-c^2 x^2}}+\frac {b c \left (8 c^4 d^2-23 c^2 d e+23 e^2\right ) \sqrt {-1-c^2 x^2} \sqrt {d+e x^2}}{75 d \sqrt {-c^2 x^2}}-\frac {4 b c \left (c^2 d-2 e\right ) \sqrt {-1-c^2 x^2} \sqrt {d+e x^2}}{75 x^2 \sqrt {-c^2 x^2}}+\frac {b c \sqrt {-1-c^2 x^2} \left (d+e x^2\right )^{3/2}}{25 x^4 \sqrt {-c^2 x^2}}-\frac {\left (d+e x^2\right )^{5/2} \left (a+b \text {csch}^{-1}(c x)\right )}{5 d x^5}+\frac {b e \left (4 c^4 d^2-11 c^2 d e+15 e^2\right ) x \sqrt {d+e x^2} F\left (\tan ^{-1}(c x)|1-\frac {e}{c^2 d}\right )}{75 d^2 \sqrt {-c^2 x^2} \sqrt {-1-c^2 x^2} \sqrt {\frac {d+e x^2}{d \left (1+c^2 x^2\right )}}}+\frac {\left (b c^3 \left (8 c^4 d^2-23 c^2 d e+23 e^2\right ) x\right ) \int \frac {\sqrt {d+e x^2}}{\left (-1-c^2 x^2\right )^{3/2}} \, dx}{75 d \sqrt {-c^2 x^2}}\\ &=\frac {b c^3 \left (8 c^4 d^2-23 c^2 d e+23 e^2\right ) x^2 \sqrt {d+e x^2}}{75 d \sqrt {-c^2 x^2} \sqrt {-1-c^2 x^2}}+\frac {b c \left (8 c^4 d^2-23 c^2 d e+23 e^2\right ) \sqrt {-1-c^2 x^2} \sqrt {d+e x^2}}{75 d \sqrt {-c^2 x^2}}-\frac {4 b c \left (c^2 d-2 e\right ) \sqrt {-1-c^2 x^2} \sqrt {d+e x^2}}{75 x^2 \sqrt {-c^2 x^2}}+\frac {b c \sqrt {-1-c^2 x^2} \left (d+e x^2\right )^{3/2}}{25 x^4 \sqrt {-c^2 x^2}}-\frac {\left (d+e x^2\right )^{5/2} \left (a+b \text {csch}^{-1}(c x)\right )}{5 d x^5}-\frac {b c^2 \left (8 c^4 d^2-23 c^2 d e+23 e^2\right ) x \sqrt {d+e x^2} E\left (\tan ^{-1}(c x)|1-\frac {e}{c^2 d}\right )}{75 d \sqrt {-c^2 x^2} \sqrt {-1-c^2 x^2} \sqrt {\frac {d+e x^2}{d \left (1+c^2 x^2\right )}}}+\frac {b e \left (4 c^4 d^2-11 c^2 d e+15 e^2\right ) x \sqrt {d+e x^2} F\left (\tan ^{-1}(c x)|1-\frac {e}{c^2 d}\right )}{75 d^2 \sqrt {-c^2 x^2} \sqrt {-1-c^2 x^2} \sqrt {\frac {d+e x^2}{d \left (1+c^2 x^2\right )}}}\\ \end {align*}

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Mathematica [C]  time = 0.70, size = 291, normalized size = 0.59 \[ \frac {\sqrt {d+e x^2} \left (-15 a \left (d+e x^2\right )^2+b c x \sqrt {\frac {1}{c^2 x^2}+1} \left (d e x^2 \left (11-23 c^2 x^2\right )+d^2 \left (8 c^4 x^4-4 c^2 x^2+3\right )+23 e^2 x^4\right )-15 b \text {csch}^{-1}(c x) \left (d+e x^2\right )^2\right )}{75 d x^5}+\frac {i b c x \sqrt {\frac {1}{c^2 x^2}+1} \sqrt {\frac {e x^2}{d}+1} \left (c^2 d \left (8 c^4 d^2-23 c^2 d e+23 e^2\right ) E\left (i \sinh ^{-1}\left (\sqrt {c^2} x\right )|\frac {e}{c^2 d}\right )+\left (-8 c^6 d^3+27 c^4 d^2 e-34 c^2 d e^2+15 e^3\right ) F\left (i \sinh ^{-1}\left (\sqrt {c^2} x\right )|\frac {e}{c^2 d}\right )\right )}{75 \sqrt {c^2} d \sqrt {c^2 x^2+1} \sqrt {d+e x^2}} \]

Antiderivative was successfully verified.

[In]

Integrate[((d + e*x^2)^(3/2)*(a + b*ArcCsch[c*x]))/x^6,x]

[Out]

(Sqrt[d + e*x^2]*(-15*a*(d + e*x^2)^2 + b*c*Sqrt[1 + 1/(c^2*x^2)]*x*(23*e^2*x^4 + d*e*x^2*(11 - 23*c^2*x^2) +
d^2*(3 - 4*c^2*x^2 + 8*c^4*x^4)) - 15*b*(d + e*x^2)^2*ArcCsch[c*x]))/(75*d*x^5) + ((I/75)*b*c*Sqrt[1 + 1/(c^2*
x^2)]*x*Sqrt[1 + (e*x^2)/d]*(c^2*d*(8*c^4*d^2 - 23*c^2*d*e + 23*e^2)*EllipticE[I*ArcSinh[Sqrt[c^2]*x], e/(c^2*
d)] + (-8*c^6*d^3 + 27*c^4*d^2*e - 34*c^2*d*e^2 + 15*e^3)*EllipticF[I*ArcSinh[Sqrt[c^2]*x], e/(c^2*d)]))/(Sqrt
[c^2]*d*Sqrt[1 + c^2*x^2]*Sqrt[d + e*x^2])

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fricas [F]  time = 0.58, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {{\left (a e x^{2} + a d + {\left (b e x^{2} + b d\right )} \operatorname {arcsch}\left (c x\right )\right )} \sqrt {e x^{2} + d}}{x^{6}}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x^2+d)^(3/2)*(a+b*arccsch(c*x))/x^6,x, algorithm="fricas")

[Out]

integral((a*e*x^2 + a*d + (b*e*x^2 + b*d)*arccsch(c*x))*sqrt(e*x^2 + d)/x^6, x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (e x^{2} + d\right )}^{\frac {3}{2}} {\left (b \operatorname {arcsch}\left (c x\right ) + a\right )}}{x^{6}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x^2+d)^(3/2)*(a+b*arccsch(c*x))/x^6,x, algorithm="giac")

[Out]

integrate((e*x^2 + d)^(3/2)*(b*arccsch(c*x) + a)/x^6, x)

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maple [F]  time = 0.43, size = 0, normalized size = 0.00 \[ \int \frac {\left (e \,x^{2}+d \right )^{\frac {3}{2}} \left (a +b \,\mathrm {arccsch}\left (c x \right )\right )}{x^{6}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((e*x^2+d)^(3/2)*(a+b*arccsch(c*x))/x^6,x)

[Out]

int((e*x^2+d)^(3/2)*(a+b*arccsch(c*x))/x^6,x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ -\frac {1}{5} \, b {\left (\frac {{\left (e^{2} x^{4} + 2 \, d e x^{2} + d^{2}\right )} \sqrt {e x^{2} + d} \log \left (\sqrt {c^{2} x^{2} + 1} + 1\right )}{d x^{5}} + 5 \, \int -\frac {{\left (c^{2} e^{2} x^{6} - {\left (5 \, d e \log \relax (c) - 2 \, d e\right )} c^{2} x^{4} - {\left ({\left (5 \, d^{2} \log \relax (c) - d^{2}\right )} c^{2} + 5 \, d e \log \relax (c)\right )} x^{2} - 5 \, d^{2} \log \relax (c) - 5 \, {\left (c^{2} d e x^{4} + {\left (c^{2} d^{2} + d e\right )} x^{2} + d^{2}\right )} \log \relax (x)\right )} \sqrt {e x^{2} + d}}{5 \, {\left (c^{2} d x^{8} + d x^{6}\right )}}\,{d x} + 5 \, \int \frac {{\left (c^{2} e^{2} x^{4} + 2 \, c^{2} d e x^{2} + c^{2} d^{2}\right )} \sqrt {e x^{2} + d}}{5 \, {\left (c^{2} d x^{6} + d x^{4} + {\left (c^{2} d x^{6} + d x^{4}\right )} \sqrt {c^{2} x^{2} + 1}\right )}}\,{d x}\right )} - \frac {{\left (e x^{2} + d\right )}^{\frac {5}{2}} a}{5 \, d x^{5}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x^2+d)^(3/2)*(a+b*arccsch(c*x))/x^6,x, algorithm="maxima")

[Out]

-1/5*b*((e^2*x^4 + 2*d*e*x^2 + d^2)*sqrt(e*x^2 + d)*log(sqrt(c^2*x^2 + 1) + 1)/(d*x^5) + 5*integrate(-1/5*(c^2
*e^2*x^6 - (5*d*e*log(c) - 2*d*e)*c^2*x^4 - ((5*d^2*log(c) - d^2)*c^2 + 5*d*e*log(c))*x^2 - 5*d^2*log(c) - 5*(
c^2*d*e*x^4 + (c^2*d^2 + d*e)*x^2 + d^2)*log(x))*sqrt(e*x^2 + d)/(c^2*d*x^8 + d*x^6), x) + 5*integrate(1/5*(c^
2*e^2*x^4 + 2*c^2*d*e*x^2 + c^2*d^2)*sqrt(e*x^2 + d)/(c^2*d*x^6 + d*x^4 + (c^2*d*x^6 + d*x^4)*sqrt(c^2*x^2 + 1
)), x)) - 1/5*(e*x^2 + d)^(5/2)*a/(d*x^5)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {{\left (e\,x^2+d\right )}^{3/2}\,\left (a+b\,\mathrm {asinh}\left (\frac {1}{c\,x}\right )\right )}{x^6} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((d + e*x^2)^(3/2)*(a + b*asinh(1/(c*x))))/x^6,x)

[Out]

int(((d + e*x^2)^(3/2)*(a + b*asinh(1/(c*x))))/x^6, x)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x**2+d)**(3/2)*(a+b*acsch(c*x))/x**6,x)

[Out]

Timed out

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